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Triangular pyramid volume calculator

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What is a triangular pyramid?

A triangular pyramid, also known as a tetrahedron, is a three-dimensional geometric figure with a triangular base and three triangular faces converging at a singular vertex point, not on the plane of the base. The triangular pyramid is a type of polyhedron, specifically comprising four triangular faces, six edges, and four vertices.

Formula for triangular pyramid volume

The volume VV of a triangular pyramid can be found using various methods depending on the known parameters of the pyramid:

1. Volume based on base area and height

V=13×Abase×HV = \frac{1}{3} \times A_{\text{base}} \times H Where:

  • AbaseA_{\text{base}} is the area of the triangular base
  • HH is the height of the pyramid from the base to the apex

2. Volume with known three sides of the base

When the three sides aa, bb, and cc of the triangular base are known, and HH, the height of the pyramid, is provided, we compute the base area using Heron’s Formula:

  1. Compute the semi-perimeter ss: s=a+b+c2s = \frac{a + b + c}{2}
  2. Use Heron’s Formula for base area AbaseA_{\text{base}}: Abase=s(sa)(sb)(sc)A_{\text{base}} = \sqrt{s(s-a)(s-b)(s-c)}
  3. Substitute AbaseA_{\text{base}} into the volume formula: V=13×s(sa)(sb)(sc)×HV = \frac{1}{3} \times \sqrt{s(s-a)(s-b)(s-c)} \times H

3. Volume with two sides and the included angle

When two sides aa and bb of the base and the included angle α\alpha are known: Abase=12×a×b×sin(α)A_{\text{base}} = \frac{1}{2} \times a \times b \times \sin(\alpha) Then use the area in the volume formula.

4. Volume with one side and two adjacent angles

When the side bb of the base and its two adjacent angles, α\alpha and β\beta, are known, you can use the Sine Rule to find the area of the base: Abase=b2×sin(α)×sin(β)2×sin(α+β)A_{\text{base}} = \frac{b^2 \times \sin(\alpha) \times \sin(\beta)}{2 \times \sin(\alpha + \beta)} Utilize this AbaseA_{\text{base}} in the volume formula.

5. Volume with known base height and side

If the base height hbaseh_{\text{base}} and the side bb of the triangular base are given: Abase=12×b×hbaseA_{\text{base}} = \frac{1}{2} \times b \times h_{\text{base}} Incorporate into the same volume equation.

Understanding correct and incorrect triangular pyramid

Regular triangular pyramid (tetrahedron)

A regular tetrahedron is a triangular pyramid where all edges are equal, and all faces are regular triangles. If the edge length is aa, the volume is calculated using the formula: V=212×a3V = \frac{\sqrt{2}}{12} \times a^3

Note: In some sources, the term “regular triangular pyramid” refers to a pyramid with a regular triangle in the base and equal side edges, but not necessarily with equal base edges and side edges. In this case, the volume formula will depend on the height of the pyramid and the area of the base.

Irregular (or incorrect) triangular pyramid

An irregular triangular pyramid has sides of varying lengths and does not exhibit uniformity in angles or edge measurements. The volume calculation relies on known measurements such as different side lengths and corresponding heights.

If the coordinates of the vertices of a triangular pyramid are known

If the coordinates of the vertices of a triangular pyramid are known, you can use an alternative method by using the tetrahedron volume calculator. By determining the coordinates of the vertices in three-dimensional space, it becomes possible to calculate using vector mathematics. This tool is useful when the pyramid does not match the clear measurements of height and base area.

Examples of volume calculation

Example 1: Known base area and height

Let’s calculate the volume for a triangular base area of 6cm26 \, \text{cm}^2 and pyramid height 9cm9 \, \text{cm}. V=13×6×9=18cm3V = \frac{1}{3} \times 6 \times 9 = 18 \, \text{cm}^3

Example 2: Volume with three known sides

Given side lengths a=3cma = 3 \, \text{cm}, b=4cmb = 4 \, \text{cm}, c=5cmc = 5 \, \text{cm}, and pyramid height 10cm10 \, \text{cm}:

  1. Calculate semi-perimeter s=3+4+52=6s = \frac{3 + 4 + 5}{2} = 6
  2. Base area Abase=6(63)(64)(65)=6×3×2×1=36=6cm2A_{\text{base}} = \sqrt{6(6-3)(6-4)(6-5)} = \sqrt{6 \times 3 \times 2 \times 1} = \sqrt{36} = 6 \, \text{cm}^2
  3. Volume V=13×6×10=20cm3V = \frac{1}{3} \times 6 \times 10 = 20 \, \text{cm}^3

Example 3: Known two sides and included angle

For a triangular base with a=5cma = 5 \, \text{cm}, b=6cmb = 6 \, \text{cm}, angle θ=60\theta = 60^\circ, and pyramid height 8cm8 \, \text{cm}:

  1. Base area Abase=12×5×6×sin(60)=1532cm2A_{\text{base}} = \frac{1}{2} \times 5 \times 6 \times \sin(60^\circ) = \frac{15\sqrt{3}}{2} \, \text{cm}^2
  2. Volume V=13×1532×8=203cm3V = \frac{1}{3} \times \frac{15\sqrt{3}}{2} \times 8 = 20\sqrt{3} \, \text{cm}^3

Frequently Asked Questions

What is the volume of a triangular pyramid if the base area and height are known?

The volume of a triangular pyramid is one-third of the product of the base area and height.

How many triangular faces does a pyramid have?

A triangular pyramid consists of four triangular faces: the base and three side faces.

Can a triangular pyramid have a horizontal base?

Yes, the base of a triangular pyramid is often horizontal in conventional illustrations, although in reality it can be oriented in any position relative to another reference plane.

What is the difference between a triangular pyramid and a tetrahedron?

A tetrahedron is a polyhedron with four triangular faces, which can be regular (all edges and angles are equal) or irregular. A triangular pyramid is a special case of a tetrahedron, where one face is the base, and the other three are side faces. Therefore, all triangular pyramids are tetrahedrons, but not all tetrahedrons necessarily have a designated base.

What is the volume of a regular triangular pyramid if the base edge length is 3?

For a regular tetrahedron or a regular triangular pyramid (where all edges are equal), the volume is calculated using the formula: V=212×a3V = \frac{\sqrt{2}}{12} \times a^3 Substituting a=3a = 3: V=212×33=212×27=27212=924V = \frac{\sqrt{2}}{12} \times 3^3 = \frac{\sqrt{2}}{12} \times 27 = \frac{27\sqrt{2}}{12} = \frac{9\sqrt{2}}{4}

The volume of a regular triangular pyramid is 3.182 cm³.

Note: If the term “regular triangular pyramid” refers to a pyramid with a regular triangle in the base and equal side edges, but not necessarily with equal base edges and side edges, then the volume formula will depend on the height of the pyramid and the area of the base. In this case, the volume formula will depend on the height of the pyramid and the area of the base.